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13s^2+4s-9=0
a = 13; b = 4; c = -9;
Δ = b2-4ac
Δ = 42-4·13·(-9)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-22}{2*13}=\frac{-26}{26} =-1 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+22}{2*13}=\frac{18}{26} =9/13 $
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